WebI am trying to get the all records which are 2 hours or more old using this query: $minutes = 60 * 2 SELECT COUNT (id) AS TOTAL, job_id from tlb_stats WHERE log_time >= DATE_SUB (CURRENT_DATE, INTERVAL $minutes MINUTE) GROUP BY job_id It only selects the recent records and skips the old. WebFeb 9, 2024 · AT TIME ZONE. 9.9.5. Current Date/Time. 9.9.6. Delaying Execution. Table 9.33 shows the available functions for date/time value processing, with details appearing in the following subsections. Table 9.32 illustrates the behaviors of the basic arithmetic operators ( +, *, etc.). For formatting functions, refer to Section 9.8.
MySQL DATE_SUB() function - w3resource
WebApr 30, 2016 · Impala Date and Time Functions The underlying Impala data type for date and time data is TIMESTAMP, which has both a date and a time portion. Functions that … WebDec 22, 2011 · time > DATE_SUB ( NOW (), INTERVAL 24 HOUR) rather than time < DATE_SUB ( NOW (), INTERVAL 24 HOUR) Share Improve this answer Follow answered Dec 22, 2011 at 11:58 Mark Baker 208k 31 340 383 thats what i have been trying but it just seems to show nothing. i think its my code then. – chris Dec 22, 2011 at 12:02 in any real sense
SQL DATE_SUB – SQL Tutorial – Learn SQL Online
WebWe have illustrated the use of DATE_SUB() to get the date and time of the past 1 hour, based on the current date and time, i.e. output of the NOW() function. Example #4. Find the date and time after an interval of 1 year based on the current timestamp. SELECT DATE_ADD(NOW(), INTERVAL 1 YEAR); WebApr 30, 2016 · The underlying Impala data type for date and time data is TIMESTAMP, which has both a date and a time portion.Functions that extract a single field, such as hour() or minute(), typically return an integer value.Functions that format the date portion, such as date_add() or to_date(), typically return a string value. You can also adjust a … WebMay 6, 2010 · If you grouped by HOUR (time) then you should use HOUR (time) in your select expressions, and not time. For example: SELECT HOUR (time), COUNT (*) FROM `records` WHERE time > DATE_SUB (NOW (), INTERVAL 24 HOUR) GROUP BY HOUR (time) ORDER BY HOUR (time) Alternatively you can group by the expression you want … in any polynomial what is standard form