Drying poj - 3104
http://poj.org/problem?id=3104 Web27 apr 2014 · POJ 3104 Drying 晾衣服:n件衣服各含a_i水分,自然干一分钟一单位,放烘干机一分钟k单位,一次只能晒一件。 求最短时间。 取C (mid) := 能在mid分钟内处理 …
Drying poj - 3104
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Webposted @ 2024-03-26 16:21 funforever 阅读 (190) 评论 (0) 推荐 (0) 编辑. 2024年3月18日. 挑战程序设计竞赛3.2例题:Physics Experiment POJ - 3684. 摘要: Simon is doing a physics experiment with N identical balls with the same radius of R centimeters. Before the experiment, all N balls are fastened with 阅读全文. Web挑战程序设计竞赛3.1习题:Drying POJ - 3104. It is very hard to wash and especially to dry clothes in winter. But Jane is a very smart girl. She is not afraid of this boring process. Jane has decided to use a radiator to make drying faster.
Web12 apr 2024 · 3.POJ 3104 Drying (二分&最大化最小值) 4.UVa 10664 Luggage (0-1背包) 5.铺瓷砖问题 HDU 2046 骨牌铺方格 + POJ 2663 Tri Tiling (递推) WebIt is very hard to wash and especially to dry clothes in winter. But Jane is a very smart girl. She is not afraid of this boring process. Jane has decided to use a radiator to make drying faster.
WebPOJ 3104 Drying 二分. POJ 3104 Drying 题意 给定n件衣服,每件衣服都有一定的湿度,有两种让衣服 变干 的方法,一种是自然晾干,每分钟减少一个湿度 (不在暖气上的衣服),另一种是用暖气片,每分钟减少k个湿… 2024/4/10 10:10:15 Web6 ago 2016 · 传送门:poj 3104 Drying题目大意有一些衣服,每件衣服有一定水量,有一个烘干机,每次可以烘一件衣服,每分钟可以烘掉k滴水。 每件衣服没分钟可以自动蒸发 …
Web16 giu 2024 · POJ 3104 Drying DryingTime Limit: 2000MS Memory Limit: 65536KDescriptionIt is very hard to wash and especially to dry clothes in winter. But …
Web19 ott 2024 · poj 3104 二分. Drying Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 12568 Accepted: 3243 Descripti ... Drying POJ - 3104. It is very hard to wash and especially to dry clothes in winter. But Jane is a very smart girl. planning portal north norfolkWebEnlace del título:POJ - 3104 . El significado: Dé un conjunto de datos, cada número representa el contenido de agua de cada pieza, ahora quiere secar la ropa, hay dos … planning portal oxford city councilWeb21 nov 2024 · 传送门:poj 3104 Drying题目大意有一些衣服,每件衣服有一定水量,有一个烘干机,每次可以烘一件衣服,每分钟可以烘掉k滴水。 每件衣服没分钟可以自动蒸发 … planning portal northamptonshire councilWebCounting Offspring HDU - 3887 简单DFS序+线段树. Counting Offspring HDU - 3887 DFS序讲解 DFS序后图 题意 求每一个点子树中标号比他小的节点数 思路 用DFS求出每一个点的 in,out ,x点的所有子节点就在in[x]到out[x]之间。 planning portal oldham councilWeb24 ott 2024 · 【POJ 3273】 Monthly Expense (二分) [POJ 3273] Monthly Expense (二分) 一个农民有块地 他列了个计划表 每天要花多少钱管理 但他想用m个月来管理 就想把这个计划表切割成m个月来完毕 想知道每一个月最少花费多少 ... POJ_3104_Drying_(二分,最小化最大 … planning portal paper application formsWebThe task is to minimize the total time of drying by means of using the radiator effectively. The drying process ends when all the clothes are dry. Input. The first line contains a single integer n (1 ≤ n ≤ 100 000). The second line contains ai separated by spaces (1 ≤ ai ≤ 109). The third line contains k (1 ≤ k ≤ 109). Output planning portal pembrokeshire county councilWeb4 apr 2024 · 3. 2. 题意:有n件衣服带有不同的水分,自然晾每分钟减少一个水分,烘***烘每分钟减少k个水分(烘***只有一个)。. 让你求这n个衣服全部晾干最少要几分钟。. 思路:. 刚开始我想每分钟过后找最大的用烘***,其余自然晾。. 这样每次都要遍历所有衣服一边 ... planning portal peak district