How many 176 resistors are required

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August undefined, 2024

Web1 R = x× 1 (176) 1 R = x × 1 ( 176) R = 176 x 176 x. Now, as per Ohm’s Law, we get, V I = 176 x V I = 176 x. ⇒ x = 176×5 220 = 4 x = 176 × 5 220 = 4. Hence, in order to draw the required amount of current, four 176 Ω resistors will be needed. Related Questions:

How many `176 Omega` resistors (in parallel) are required to

WebYou are given several identical resistance each of value R=10 and each capable of carrying a maximum current of one ampere. It is required to make a suitable combination of these … WebJun 24, 2024 · According to Ohm’s law, V = IR Now for x number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is 44 Ω. Therefore, … how diverse is alabama

Answered: How many 176Ω resistors (in parallel)… bartleby

WebApr 26, 2024 · Q10. How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line?Welcome to our channel, hope you will get sufficient information from o... WebMar 21, 2024 · The continued fraction (="Euclidean"?) gives contfrac(x) = [0, 1, 5] so we have x = 1 / (1 + 1 / 5) and thus x = r 5r and we need 6 resistors, which is not optimal. A better configuration is by 5 / 6 = 1 / 2 + 1 / 3 = 2r ⊕ 3r so we need 5 resistors. WebSolution Verified by Toppr Step 1 : Equivalent resistance Let n be the number of resistors to be connected in parallel Then, R 1=R 2=......=R n=R=176 Ω Now, R eq1 = R 11+ R 21 +..... R n1 ⇒ R eq1 = R 1n= 176n ⇒R eq=176/n ....(1) Step 2 : Applying Ohm’s law V=IR eq ⇒220=5R eq ⇒220=5×176/n ( Using Equation (1)) ⇒n=4 how diverse groups changed australian society

How many resistors are needed? - Mathematics Stack Exchange

WebAns: For x number of resistors of resistance 176 Ω, Here Supply voltage, V = 220 V Current, I = 5 A Equivalent resistance of the combination = R, given as From Ohm’s law, ∴four … WebJun 17, 2016 · Now for x number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is 44 Ω. 1/44 = 1/176 + 1/176 + 1/176 .....χ times. 1/44 = x / 176 => x = 176/ 44 => x = 4. Therefore, 4 resistors of 176 Ω are required to draw the given amount of current. I hope, this will help you___ . Thank you how diverse is cornwallWebFind many great new & used options and get the best deals for Ohmite Two Ganged 35 Ohm 1.0 Amp Wire Wound Potentiometers at the best online prices at eBay! ... Vitreous Enamel Adjustable Wire-Wound Power Resistors, 100 Watts. $5.59 + $4.50 shipping. Ohmite 12 Ohm 2.04 Amp Wire Wound Potentiometer ... Minimum monthly payments are required ... how diverse is aboriginal culture

"WebApr 29, 2024 · Q 10: How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? From Ohm’s law, ∴four resistors of 176 Ω are required to draw the given amount of current. When three equal resistance are connected in parallel the effective resistance is 1 by 3 home if all are connected in series the effective resistance is? " - How many 176 resistors are required

How many 176 resistors are required

How many 176 ohm resistors (in parallel) are required to carry 5 A …

WebHow many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? DARSHAN CLASSES 9,159 views Apr 26, 2024 Q10. How many 176 Ω resistors (in parallel) are … WebSolution for How many 176Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Skip to main content. close. Start your trial now! First week only $4.99! arrow ... How many 176Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Expert Solution. Want to see the full answer? Check out a sample Q&A here.

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WebMar 14, 2024 · Hence using the Ohm’s law and the value of resistance from equation (1), we get: V = I R n e t ⇒ 220 = 5 ( 176 N) ⇒ N = ( 176 44) ⇒ N = 4. Hence, 4 of the 176 Ω resistors in parallel would be required to get a net current of 5A flowing through a 220V line. WebApr 8, 2024 · Complete step by step answer: We have given here to find the number of \ [176\Omega \] resistors needed to carry \ [5A\] on a \ [220V\] line. Let, the number of resistors needed is \ [x\]. Hence, the equivalent resistance of the \ [x\] number of resistors will be when connected in parallel,

WebMar 29, 2024 · (a) For highest resistance according to question resistances must be connected in series: 4 Ω, 8 Ω, 12 Ω, 24 Ω R 1 = 4 Ω R 2 = 8 Ω R 3 = 12 Ω R 4 = 24 Ω Total resistance in series = R 1 + R 2 + R 3 + R 4 = 4 + 8 + 12 + 24 = 48 Ω Now, resistance is maximum when connected in series. WebClick here👆to get an answer to your question ️ How many 176 Ω ?resistor(in parallel) are required to carry 5 A in 220 V line. Solve Study Textbooks Guides. Join / Login. Question . ... Calculate the equivalent resistance of the two resistors of 100 ...

WebApr 30, 2024 · 4 Resistors are required. Step-by-step explanation: Given: Volts = 220 Volts. Current = 5 Ampere. Resistance of each resistor, R = 176 Ohms. No of resistors = n. We know that: v = RpI. ∴ ∵ . Taking N to the other side we … WebQ 10: How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Ans: For x number of resistors of resistance 176 Ω, Here Supply voltage, V = 220 V Current, I = 5 A Equivalent resistance of the combination = R, given as From Ohm’s law, ∴four resistors of 176 Ω are required to draw the given amount of current. Important Links

WebMar 24, 2024 · Best answer Let the resistors be x’ Resistance = 176Ω As per ohm’s law . V = IR R = V I V I Here, V = 220 V, I = 5A ∴ Four resistors (in parallel) are required to carry 5A on a 220 V line. ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series NEET Test Series Class 12 Chapterwise MCQ Test Class 11 Chapterwise Practice …

WebI ( current ) = V (voltage ) / R ( resistance ) . hence to carry 5A at 220 V supply Resistance required V / I = 220 / 5 = 44 OHMS. In parallel circuit 1/R = 1/R1 + 1/ R2 + 1 / R3 so on …. Hence 1 / 44 = n / 176 when n = no of parallel resistance so n = 176 / … how diverse is columbia moWebAnd then we get One upon. Our total is going to want upon 44 because the maximum resistance will be 44. So and upon 1 76. If we solve this, If we solve this then we get and … how diverse is bradfordWebTo calculate the number of 176 ohm resistors required in parallel to achieve a specific resistance, you need to use the following formula: N = R_desired / R_single Where N is the … how diverse is austriaWebQuestion How many 176 ohm resistors are required to carry 5A on 220V line Solution Voltage= 220V Current = 5A R=V/I Therefore, R = V/I = 220/5 = 44ohm Resistance= 44ohm … how diverse is chandler azWebApr 5, 2024 · Therefore, current through 12 Ω resistor = 0.67 A. 12. How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Suppose n resistors of 176 Ω are connected in parallel. 1/R = 1/176 + 1/176 + ……….n times 1/R = n/176 or R= 176/n Ω By Ohm’s law R=V/I 176/n = 220/5 n= (176 x 5)/220 = 4 13. how diverse is houstonWebR_total = (R1 * R2) / (R1 + R2) Where R1 and R2 are the values of the two resistors. To calculate the number of 176 ohm resistors required in parallel to achieve a specific resistance, you need to use the following formula: how diverse is dallasWebApr 8, 2024 · Hint: The equation for the net resistance for two resistors of resistances connected in parallel hast to be used first. Further, Ohm's law and Kirchoff’s current law will also be used to find the number of resistors. Formula used: The net resistance for two resistors of three resistances \[({R_1}),({R_2})\]and \[\left( {{R_3}} \right)\] connected in … how diverse is florida