WebSolution: As we know, magnetic field at the center of a circular coil carrying current I of radius R is given by, B= 4πRμ2πI= 2RμI (1) So, magnetic field at a point along axis of circular coil at distance R from the center is given by, B a= 4π(R 2+R 2) 23μ2πIR 2 = 2 8RμI = 8B (From (1)) Hence, the correct option is (C). Was this answer helpful? 0 0 Web326 views, 14 likes, 0 loves, 0 comments, 7 shares, Facebook Watch Videos from The PSM: Magnetic Field due to a Current Carrying Circular Coil
Experiment 67 HALL PROBE MEASUREMENT OF …
WebThe magnetic field due to a single circular current loop at an arbitrary point in space is shown in Fig. 1. It is a rather complicated function of the coordinates. Figure 1. Field … WebDraw the magnetic field lines due to a circular wire carrying current I. Open in App. Solution. Imagine a circular coil of radius R with centre O.Let the current flowing through the circular loop be I. suppose P is any point on the axis at a distance of r from the centre 0. Let the circular coil be made up of a large number of small elements of ... eaa virtual flight academy download
Derive an expression of the magnetic field at the centre of a circular
WebMagnetic field due to current-carrying coil When a current flows in a wire, it creates a circular magnetic field around the wire. This magnetic field can deflect the needle of a... WebApr 14, 2024 · The magnetic field at the centre of a current carrying circular coil of radius \( 10 \mathrm{~cm} \) is \( 5 \sqrt{5} \) times the magnetic field at a point ... WebNov 24, 2024 · SI unit of the magnetic field is the tesla (T). The magnetic field at the centre of a circular coil is given by: \(B = \;\frac{{{\mu _0{}}I}}{{2R}}\) Where. B= magnetic field at the centre of the coil, μ 0 = the permeability of free space = 4π × 10-7, I = current and R is the radius of the circular coil. Explanation: eaa video player